This is a hard questions to answer since I have to explain how intel MTX works and I don't know how it works 100% but here I am going to try :)
At the beginning I though that IDA was giving you wrong disassemble code (that's not true I'll explain that later).
Since you give me extra info (opcodes) I assemble it with rasm2 and I got this:
$ rasm2 -a x86 -d "F2 EB F5"
bnd jmp 0xfffffff8
BND! that is not a illegal instruction, actually it is call an Intel MPX (Memory Protection Extensions) It was first announced in 2013 and introduced in 2015.
Intel MPX is a set of extensions to the x86 instruction
set architecture. With compiler, runtime library and operating system
support, Intel MPX brings increased security to software by checking
pointer references whose normal compile-time intentions are
maliciously exploited at runtime due to buffer overflows.
Intel MPX provides four new registers named bnd0-bnd3 that are use to set bounds to avoid memory attack. I recommend you to read this, this, and this.
Getting back to your question. I think is going to work as a normal jmp because the bound registers are not initialized. How I know that? Your opcode is EB and if you read the articles you will read this.
An application compiled to use Intel MPX will use the REPNE (F2H)
prefix (denoted by BND) for all forms of near CALL, near RET, near
JMP, short & near Jcc instructions (BND+CALL, BND+RET, BND+JMP,
BND+Jcc). See Table 17-4 for specific opcodes. All far CALL, RET and
JMP instructions plus short JMP (JMP rel 8, opcode EB) instructions
will never cause bound registers to be initialized
Reading that I also understand why IDA was not giving you wrong code.