I am solving a crack me challenge but I am stuck. The challenge executes several jne
tests. The first test is the simpliest but I don't arrive to print the eax
value to know the content of cmp
instruction. According to this block of code :
| ; DATA XREF from sym.main (0x804848e)
| 0x08048497 b88a55ea8b mov eax, 0x8bea558a
| 0x0804849c 45 inc ebp
| 0x0804849d f4 hlt
| 0x0804849e 83c004 add eax, 4
| 0x080484a1 8a00 mov al, byte [eax]
| 0x080484a3 38c2 cmp dl, al
|,=< 0x080484a5 753d jne 0x80484e4
How can I print the eax
value to understand what are compared in the instruction ?
0x080484a1 8a00 mov al, byte [eax]
According to this question, I tried the 0x080484a1
but when I enter the command pxr 1 @ eax+0x4
, nothing appears. If I enter the command pxr @ eax+0x4
, this code appears :
0x080c288c 0x6f6c6165 ealo ascii
0x080c2890 0x00796768 hgy. ascii
The ascii printed is linked with the string compared ksuiealohgy
.