I was wondering if it was possible to create a python script that is able to capture and replay the instructions executed by a windows program for in depth analysis.

  • It's probably possible, if you could control the time-travel debugging feature of WinDbgX via Python. But could you explain what you have already tried and what you are stuck on? This sounds like a very broad question. And the answer is: probably yes. But I doubt that's the answer you are looking for. So What is it you are looking for?
    – 0xC0000022L
    Jan 19, 2023 at 14:08

1 Answer 1


Here is an example of how you could use the pyDbg library in Python to create a basic script that captures and replays the instructions executed by a Windows program:

import pydbg

def main():
    # Create a new instance of the pydbg class
dbg = pydbg()

# Attach to the process of the target program
pid = dbg.attach("program.exe")

# Set a breakpoint at the entry point of the program
entry_point = dbg.func_resolve("program.exe", "main")

# Start the debugging loop

# Once the program has exited, print the instructions that were executed
print("Instructions executed:")
for instruction in dbg.instructions:
    print("0x%08x: %s %s" % (instruction[0], instruction[1], instruction[2]))

if __name__ == "__main__":

As the program runs, the script will capture the executed instructions and save them in a list. Once the program has exited, the script will print out the executed instructions. Note that this is just a very basic example, and it is not robust enough for a real-world use case. In a real-world application, you need to consider factors such as handling multiple threads, exceptions and system calls, and more.

  • Hi and welcome to RE.SE. This looks and sounds very much like an AI-generated answer (flagging as such). Is it? As a side-note: pydbg from Pedram Amini and all continuations/successor projects I found is for Python 2.7, which is out of support. I used pydbg myself back in the day. If you are aware of a modern Python-3.x-enabled continuation or successor, please add a link, too.
    – 0xC0000022L
    Jan 19, 2023 at 14:20

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