Want to get 32 bits from 0x8000 adress as 8 bytes
MEM_EXT:00008000 db 54h
MEM_EXT:00008001 db 53h, 57h, 20h
MEM_EXT:00008004 dd 322E3256h, 31332030h, 30303330h, 31313320h, 43432036h
MEM_EXT:00008004 dd 2F363535h, 20425345h, 865808FAh, 865808FAh, 865808FAh
MEM_EXT:00008004 dd 865808FAh, 865808FAh, 865808FAh, 865808FAh, 865808FAh
MEM_EXT:00008004 dd 865808FAh, 865808FAh, 865808FAh, 0FFA735A7h, 962F8E20h
MEM_EXT:00008004 dd 0DF00F0h, 0DF00FFh, 0AF008Fh, 70002h, 380038h, 0FF000700h
MEM_EXT:00008004 dd 0, 0, 0
Would this be
0x54 0x53 0x57 0x20 0x32 0x2e 0x32 0x56 ???
How to get further 64 bits, after first 32 bits from 0x8000?
Weird things is that 64 bits as 16 bytes should contain also 0 somwehere
Those should be permutation and S-box key parts
Some more info:
ROM:00000000 ; Processor : c166 [C165]
ROM:00000000 ; Target assembler: Keil A166 Assembler
ROM:00000000 ; Byte sex : Little endian