I came across this part in the book Reverse Engineering For Beginners book by Denis Yurichev. It writes about reverse engineering Classes in C++, but it doesn't provide any examples in ARM.
Page 546
_this$ = -4
; size = 4
??0c@@QAE@XZ PROC ; c::c, COMDAT
; _this$ = ecx
push ebp
mov ebp, esp
push ecx
mov DWORD PTR _this$[ebp], ecx
mov eax, DWORD PTR _this$[ebp]
mov DWORD PTR [eax], 667
mov ecx, DWORD PTR _this$[ebp]
mov DWORD PTR [ecx+4], 999
mov eax, DWORD PTR _this$[ebp]
mov esp, ebp
pop ebp
ret 0
??0c@@QAE@XZ ENDP ; c::c
_this$ = -4 ; size = 4
_a$ = 8
; size = 4
_b$ = 12
; size = 4
??0c@@QAE@HH@Z PROC ; c::c, COMDAT
; _this$ = ecx
push ebp
mov ebp, esp
push ecx
mov DWORD PTR _this$[ebp], ecx
mov eax, DWORD PTR _this$[ebp]
mov ecx, DWORD PTR _a$[ebp]
mov DWORD PTR [eax], ecx
mov edx, DWORD PTR _this$[ebp]
mov eax, DWORD PTR _b$[ebp]
mov DWORD PTR [edx+4], eax
mov eax, DWORD PTR _this$[ebp]
mov esp, ebp
pop ebp
ret 8
??0c@@QAE@HH@Z ENDP ; c::c
As you can see ECX is used to hold the pointer of this for accessing the members of the class. How is this done in ARM assembly?