How to pass param to execve to execute cat a file in x64 Asm? [closed]

Question

I want execve("/bin/cat",["/bin/cat","/test/file"],NULL).

Here is my asm

xor %rdx, %rdx 
push %rdx

sub $0x16, %rsp
movb $0x2f, 7(%rsp)
movl $0x2f6e6962, 8(%rsp)
movl $0x746163, 12(%rsp)
leaq 7(%rsp), %rdi

pushq %rdx

push %rdi

mov %rsp, %rsi

movb $0x3b, %al 
syscall

This asm, I can get only `execve("/bin/cat",["/bin/cat"],NULL) only.

How can I pass param '/test/file' in rsi?

Answer 1

execve specification says:

Both argv and envp must be terminated by a NULL pointer.

but from your question it seems, that you forgot about it; you want to call it like this:

execve("/bin/cat", ["/bin/cat","/test/file", NULL], NULL)

If it still doesn't work, here is the working code in C. You can then follow @user3629249's suggestion and use gcc -S nameOfProgram to get the assembly generated, or just compile it and see the output of objdump -d nameOfProgram.

#include <unistd.h>

int main()
{
    char* argv[3] = {"/bin/cat", "/test/file", NULL};
    execve("/bin/cat", argv, NULL);
}