This is the code I am looking at
0x0000000000401048 <+70>: mov 0x401ba0(,%rax,4),%eax
This is an array of 15 integers. Just wondering how I can access indices 0 to 15 in gdb
Thanks
8
migrated from stackoverflow.com Apr 28 '13 at 14:30
This question came from our site for professional and enthusiast programmers.
13
GDB allows you to use C-style casts, so simply do this, if you know the address:
(gdb) print/x (int[15])(*0x401ba0)
An example output would be:
$1 = {0x5241c031, 0x41535341, 0x41554154, 0x55574156, 0x48e58948, 0x31f0e483, 0x31f631ff, 0xe8c931d2, 0xfffffb08, 0xc0314850, 0x580f0174, 0x7c00f883, 0xec8948c7, 0x415f415d, 0x415d415e}
If you have the address of your array in a register, you can also use the respective variable ($eax etc).
answered Apr 28 '13 at 15:44
8
(gdb) dump binary memory dump.raw 0x401ba0 0x401bdc
dump memory into file dump.raw from address 0x401ba0 until address 0x401bdc
Another option would be examine:
x/nfu <address>
Print memory.
n: How many units to print (default 1).
f: Format character (like „print“).
u: Unit.
Unit is one of:
b: Byte,
h: Half-word (two bytes)
w: Word (four bytes)
g: Giant word (eight bytes)).
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that would make: x/15w 0x401ba0 – dbrank0 Apr 28 '13 at 8:19
4
For reading and writing to the 15 elements in the array:
(gdb) set variable $A = (int*)0x401ba0
(gdb) p $A[0] = 1
...
(gdb) p $A[14]
For examing their current value,
(gdb) x/15dw $A
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Under some circumstances
set write(==set write on) may be needed. – 0xC0000022L♦ Apr 28 '13 at 23:56
