I have this assembly code:
MOV DL,BYTE PTR DS:[ECX+EAX] --> Move the first byte of EAX to DL ADD BYTE PTR DS:[EAX+9],DL --> ADD the DL byte to the ninth byte at EAX INC ECX --> Increase ECX by one CMP ECX,DWORD PTR SS:[EBP+C] -- > ????
As you can see i understand everything except of the last line,
CMP ECX,DWORD PTR SS:[EBP+C]
What i can understand here is that there is a compersion between 4 bytes that comes from EBP+C to ECX
But i still don't understand that what is that EBP+C?