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I extracted the libc.so.6 from within a vulnerable image used for exploitation purposes. I open up the shared object in IDA and I look at the symbols inside the "Exports" tab. I find "free"; upon visiting the function however, its body seems to do something rather different from what I'd expect from a dlmalloc free implementation. What am I missing?

  • Are there any version symbols in your libc.so? Maybe you're not dealing with the standard glibc, but a very old version, or µlibc, or even a version that has custom implementations of some functions, trading memory footprint for speed, or vice versa. – Guntram Blohm supports Monica Aug 22 '15 at 12:13
  • The machine has a dynamically compiled binary that has a vulnerable binary(that can be exploited due to how dlmalloc works). ldd shows that the binary depends on this shared object. – user1743 Aug 22 '15 at 12:15
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I could not figure out why this problem happens. However, I just dumped "free" from within gdb, opened it up in IDA and it works just fine.

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