I'm browsing an old 80186 BIOS ROM in IDA free. I have loaded the binary file at the correct address and created one big segment for the entire thing since I knew nothing about the internal structure.

Now, as I have been digging around, disassembling, commenting etc, I have identified some things that I'd like to create new segments for, e.g. interrupt vector seg:offset, far jmps, jump tables that are offsets into different CS values, etc.

1. Is this how you are supposed to use IDA segments? I.e. avoid having to hand-calculate linear addresses from jump table offsets by making a new segment with the (known) CS value at the time the table is used.

2. How do I create a new segment without losing the data entered (disassembly, arrays, comments...) in the one all-encompassing segment I already have? It seems that to make room for a new segment, I need to delete or move the one that's already there, but when I do, all work done in that area (of linear addresses) is lost.

I'm browsing an old 80186 BIOS ROM in IDA free. I have loaded the binary file at the correct address and created one big segment for the entire thing since I knew nothing about the internal structure.

Now, as I have been digging around, disassembling, commenting etc, I have identified some things that I'd like to create new segments for, e.g. interrupt vector seg:offset, far jmps, jump tables that are offsets into different CS values, etc.

1. Is this how you are supposed to use IDA segments? I.e. avoid having to hand-calculate linear addresses from jump table offsets by making a new segment with the (known) CS value at the time the table is used.

2. How do I create a new segment without losing the data entered (disassembly, arrays, comments...) in the one all-encompassing segment I already have? It seems that to make room for a new segment, I need to delete or move the one that's already there, but when I do, all work done in that area (of linear addresses) is lost.

Edit: This is the ROM. It's loaded at 0xf0000-0x100000, entry point is f000:fff0 (reset vector) https://www.dropbox.com/s/63oxq39w0v3rdo9/RYSA094_joined.bin?dl=0

IDA newbie question:

I'm browsing an old 80186 BIOS ROM in IDA free. I have loaded the binary file at the correct address and created one big segment for the entire thing since I knew nothing about the internal structure.

Now, as I have been digging around, disassembling, commenting etc, I have identified some things that I'd like to create new segments for, e.g. interrupt vector seg:offset, far jmps, jump tables that are offsets into different CS values, etc.

1. Is this how you are supposed to use IDA segments? I.e. avoid having to hand-calculate linear addresses from jump table offsets by making a new segment with the (known) CS value at the time the table is used.

2. How do I create a new segment without losing the data entered (disassembly, arrays, comments...) in the one all-encompassing segment I already have? It seems that to make room for a new segment, I need to delete or move the one that's already there, but when I do, all work done in that area (of linear addresses) is lost.

I'm browsing an old 80186 BIOS ROM in IDA free. I have loaded the binary file at the correct address and created one big segment for the entire thing since I knew nothing about the internal structure.

Now, as I have been digging around, disassembling, commenting etc, I have identified some things that I'd like to create new segments for, e.g. interrupt vector seg:offset, far jmps, jump tables that are offsets into different CS values, etc.

1. Is this how you are supposed to use IDA segments? I.e. avoid having to hand-calculate linear addresses from jump table offsets by making a new segment with the (known) CS value at the time the table is used.

2. How do I create a new segment without losing the data entered (disassembly, arrays, comments...) in the one all-encompassing segment I already have? It seems that to make room for a new segment, I need to delete or move the one that's already there, but when I do, all work done in that area (of linear addresses) is lost.