Timeline for Does x86 instruction SHL/SHR actually rotate the bits?
Current License: CC BY-SA 3.0
12 events
when toggle format | what | by | license | comment | |
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Jul 18, 2017 at 17:42 | answer | added | dsasmblr | timeline score: 1 | |
Jul 18, 2017 at 14:13 | answer | added | TJ Nel | timeline score: 0 | |
Jul 17, 2017 at 18:24 | history | edited | Igor Skochinsky♦ | CC BY-SA 3.0 |
fix typo
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Jul 17, 2017 at 18:00 | history | bumped | CommunityBot | This question has answers that may be good or bad; the system has marked it active so that they can be reviewed. | |
Jun 17, 2017 at 17:13 | history | bumped | CommunityBot | This question has answers that may be good or bad; the system has marked it active so that they can be reviewed. | |
May 18, 2017 at 16:29 | history | bumped | CommunityBot | This question has answers that may be good or bad; the system has marked it active so that they can be reviewed. | |
Apr 28, 2017 at 18:25 | comment | added | peter ferrie | I also think your observation is incorrect. I don't know of any circumstances in which "shl di,cl" causes di to be unchanged when cl has any of the low 4 bits set. | |
Apr 18, 2017 at 16:03 | answer | added | Leo B. | timeline score: 2 | |
Apr 18, 2017 at 13:48 | comment | added | julian♦ | CLI is an instruction ("Clear Interrupt"), not a register. What is "cli=0x11" supposed to mean? | |
Apr 18, 2017 at 13:22 | comment | added | mrexodia |
They do not rotate. For rotation you have rol and ror . The instruction shr does however keep the sign bit if it's set.
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Apr 18, 2017 at 8:36 | comment | added | Igor Skochinsky♦ | how are your debugging it? | |
Apr 16, 2017 at 2:20 | history | asked | user15580 | CC BY-SA 3.0 |